Foam filling chassis

haha, show piece, no triangulation, no way it'll support 2000lbs in a rollover.


jimn_cage7.jpg
 
yeah its over... so if anyone wants to make any more inputs then so be it... if not then i will be posting pics i guess this weekend when we are doing this little disaster.
 
Gabe163 said:
^^^ Lets not get technical here... we laughed its over :bigthumbu
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it not being technical, is what i thought was funny as hell about it. Its some kind of equivelent to a ricer going off road!
 
I honestly don't really see how adding foam will do anything significant in regards to torsion.
For rectangular cross-sections, the maximum stress is experienced at the center of the longest sides. Therefore, adding foam to a hollow rectangular tube wouldn't really add any noticeable rigidity.
For Example:

For a solid bar of rectangular cross section, shear stress is given by t=T/(cab^2). where t=shear stress, T=torque, c=const=.208, a=b=.040m=>length of sides.
Assume the max allowable t=40MPa,solving for Torque gives Tmax= 532 N-m

Now for a hollow tube with the same dimensions t=T/(2*thickness*A)
where thickness = .006m, and A = area bounded by the center line of the cross section,
t = 40 MPa again, solving for Tmax gives 555 N-m

Good luck though. :)
 
have lots of acetone and gloves to clean that crap up, trust me we use it alot for filling and strength of fiberglass parts on boats. it can get nasty real fast. good luck cant wait to hear end result.
 
damn.... ok i will have some acetone... gloves... shit yeah i got to go buy some of those tommrow.. haha. thanks man i cant wait to get it and play around with it... nick and i will be doign this and we will be posting pics, dont worry.
 
WolfbaneDrifter said:
I honestly don't really see how adding foam will do anything significant in regards to torsion.
For rectangular cross-sections, the maximum stress is experienced at the center of the longest sides. Therefore, adding foam to a hollow rectangular tube wouldn't really add any noticeable rigidity.
For Example:

For a solid bar of rectangular cross section, shear stress is given by t=T/(cab^2). where t=shear stress, T=torque, c=const=.208, a=b=.040m=>length of sides.
Assume the max allowable t=40MPa,solving for Torque gives Tmax= 532 N-m

Now for a hollow tube with the same dimensions t=T/(2*thickness*A)
where thickness = .006m, and A = area bounded by the center line of the cross section,
t = 40 MPa again, solving for Tmax gives 555 N-m

Good luck though. :)
Click to expand...

im glad were thinking on the same page.
 
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